Question

A bus increases its velocity from 10 m/s to 30 m/s in 2.0 s find the acceleration

Answer 1

Answer:

The acceleration of the bus is $10\text{ m/s}^2$.

Explanation:

Given information:

• Initial velocity of the bus $u=10\text{ m/s}$
• Final velocity of the bus $v=30\text{ m/s}$
• Time taken$t=2\text{ s}$

The acceleration is given as,

$a=\frac{v-u}{t}$

Substituting all known values,

$a=\frac{(30\text{ m/s})-(10\text{ m/s})}{2\text{ s}}\\=10\text{ m/s}^2$

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Answer 2

Answer:

Explanation:

Initial Velocity (u) = 10m/s
Final Velocity (v) = 30m/s
Time (t) = 2.0s

Formula for Acceleration (a) = $\frac{v-u}{t}$

=$\frac{30-10}{2}$

=$\frac{20}{2}$ = 10m/$s^{2}$