Question

A bus increases its velocity from 36km/h to 54km/h in 5 second.
Calculate the acceleration?​

Answer 1

$\huge\underbrace\mathfrak\red{answer}$

in the given question we have

u=36 km/hr =36×185m/s=10m/s

v= 72 km/hr=72×185m/s=20m/s

t=10 s

a=?

we know the formula

v= u +at

20 = 10+ a 10

20-10 =10 a

10 = 10 a

a = 1 m/s2

Answer 2

Given:

• Initial velocity (u) = 36km/h
• Final velocity (v) = 54 km/h
• Time (t) = 5 sec

To Find:

• Calculate the acceleration?

Formula Used:

$\\ \bullet{\boxed{\sf\large\green{ Acceleration (a) = \dfrac{v-u}{t} }}}$

Solution:

Initial velocity (u) into m/s :- 36 × 5/18

= 10m/s

Final velocity (v) into m/s :- 54 × 5/18

= 15 m/s

$\\ \hookrightarrow{\sf{ a = \dfrac{ 15 - 10}{5} }} \\ \\ \hookrightarrow{\sf{ a = \cancel{ \dfrac{5}{5} } }} \\ \\ \hookrightarrow{\sf\pink{ a = 1 \: m/s^2 }}$

Hence,

The acceleration of the bus is 1 m/s².