Question

a bus initially at rest starts moving with a constant acceleration 1m/s2 and a covers a distance of 50 m/s calculate final velocity and time taken

Answer 1

$\small{\underline{\sf{\orange{Given:\rightarrow}}}}$

• Acceleration $\sf{[a] = 1m/s^2}$

• Distance $\sf { [s] = 50m/s}$

$\small{\underline{\sf{\purple{Find:\rightarrow}}}}$

• Final velocity?
• Time taken?

$\small{\underline{\sf{\green{Formulas \ used:\rightarrow}}}}$

• $\boxed{\sf{v^2-u^2=2as}}$

• $\boxed{\sf{a=\dfrac {v-u}{t}}}$

$\small{\underline{\sf{\blue{SoLution:\rightarrow}}}}$

• For the Final velocity, use this formula

$\implies \sf{v^2-u^2= 2as}$

$\implies \sf{v^2 - 0 = 2\times 1 \times 50 }$

$\sf{\implies v^2=100}$

$\sf{\implies v= \sqrt{100}}$

$\sf {\implies v = 10m/s }$

• Now we will find the time taken by the formula of acceleration,

$\sf {\implies a= \dfrac{v-u}{t}}$

$\sf{\implies 1= \dfrac{10-0}{t}}$

$\sf{\implies t= \dfrac{10}{1}}$

$\sf{\implies t= 1 \ sec}$

Hence, Final velocity [v]= 100m/s and time taken [t] = 1 sec.

$\rule{170}2$