Question

A bus initially at rest starts moving with an acceleration of 2 ms−2 .The time in which it picks up a velocity of 32 ms−1 is​

Answer 1

Given :

• Initial velocity (u) = 0 [ Started from rest ]
• Acceleration of bus (a) = 2m/s²
• Final velocity (v) = 32 m/s

To find :

• Time is taken to pick up a velocity of 32m/s

Solution :

• According to the first equation of motion

→ v = u + at

Where,

• v = final velocity
• u = initial velocity
• a = acceleration
• t = time

According to the question

• Substitute all the values

→ v = u + at

→ 32 = 0 + 2 × t

→ 32 = 2t

→ t = 32/2

→ t = 16 sec

•°• Time is taken to pick up a velocity of 32m/s is 16 sec.

Focus Zone :

• S.I unit of speed and velocity = m/s
• S.I unit of time = second
• The rate of change in velocity is known as Acceleration.

________________________________

Answer 2

Answer:

Given :-

• A bus initially at rest starts moving with an acceleration of 2 m/s² and the velocity is 32 m/s.

To Find :-

• What is the time.

Formula Used :-

By using first equation of motion we know that,

${\purple{\boxed{\large{\bold{v =\: u + at}}}}}$

where,

• v = Final velocity
• u = Initial velocity
• a = Acceleration
• t = Time

Solution :-

Given :

• Final velocity = 32 m/s
• Initial velocity = 0 m/s
• Acceleration = 2 m/s²

According to the question by using the formula we get,

⇒ $\sf 32 =\: 0 + 2 \times t$

⇒ $\sf 32 =\: 2 \times t$

⇒ $\sf \dfrac{\cancel{32}}{\cancel{2}} =\: t$

⇒ $\sf 16 =\: t$

➠ $\sf\bold{\red{t =\: 16\: seconds}}$

$\therefore$ The time in which it picks up a velocity of 32 m/s is 16 seconds .