Question

A bus initially at rest travels a distance 50 m in 5 s with a constant acceleration. calculate the final velocity at the end of 5 s.




​

Answer 1

Answer:

s=ut+(1/2)at

2

100=(1/2)×a×5

2

a=8 m/s

2

v=u+at

v=0+8×5=40ms

−1

.

Answer 2

Given:

A bus initially at rest travels a distance 50 m in 5 s

To find:

velocity at the end of the 5 sec

Solution:

as it is given that the body is moving with constant acceleration so we will find that first

from the second law of motion we have:

s = ut+1/2 at²

where

s = 50 m

t = 5 sec

u = 0 m/sec

by putting the values in the equation we get

• 50 = 0+1/2 a (5)²
• 100 = 25a
• a = 4 m/sec²

now from the first law of motion, we have

v = u+at

where

t = 5 sec

a = 4 m/sec²

by putting the values we get

• v = 0 + 5×4
• v = 20 m/sec

Hence the final velocity is 20 m/sec