Question

A bus is beginning to move with an acceleration of 1 ms. A
boy who is 48 m behind the bus starts running at 10 ms'.
After what time will the boy be able to catch the bus?

Answer 1

Answer:

72 + 48 = 120 m . Bus acceleration is 1 m/s2 therefore let the bus travel for t s then distance covered is 1/2at2 as u=0 then distance covered is 1/2 t^2 so boy also should travel for same t s to catch the bus so distance covered by boy=10t m then 10t=48+t^2/2 then t2-20t+96=0 then t=12 s or 8s.

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