A bus is carrying 50 passengers , some with Rs 5 tickets and the remaining with Rs 10 tickets. If the total money received passengers is Rs 350, find the number of passengers with each type of ticket.
please help me.
Answers
Topic
Linear Equations in one variable
Given
A bus is carrying 50 passengers.
Cost of some tickets is Rs. 5.
Cost of some tickets is Rs. 10.
Total money received from passengers is Rs. 350.
To Find
Number of passengers with each type of ticket.
Solving
Let number of passengers with ticket of Rs. 5 be x.
Then, number of passengers with ticket of Rs. 10 will be ( 50 - x ). As, total number of passengers are 50.
Passengers with ticket of Rs. 5 will pay total money equivalent to 5x.
( Total Money = Price of Ticket * Number of passengers )
Similarly, passengers with ticket of Rs. 10 will pay total money equivalent to
10( 50 - x ).
Total money obtained = Rs. 350
5x + 10( 50 - x ) = 350
5x + 500 - 10x = 350
500 - 5x = 350
150 = 5x
30 = x
So, passengers with ticket of Rs. 5 are 30.
And passengers with ticket of Rs. 10 are
50 - x = 50 - 30 = 20
Answer
So, number of passengers with ticket of Rs. 5 are 30 and number of passengers with ticket of Rs. 10 are 20.
Verification
We can check whether total amount is Rs. 350 or not.
So, Left Hand Side of Equation formed
5x + 10( 50 - x )
5( 30 ) + 10( 50 - 30 )
150 + 10( 20 )
150 + 200
350
It is equal to Right Hand Side.
Hence, verified.