Question

a bus is carrying 56 passengers with some people having Rs.8 tickets and remaining having Rs.10 tickets .If the total money received from the passangers is Rs.500,find the number of passangers with each ticket​

Answer 1

Answer:

★ 30 Passengers with Rs 8 ticket ★

30 Passengers with Rs 8 ticket ★★ 26 Passengers with Rs 10 ticket ★

Step-by-step explanation:

Given:

• Total number of passengers in bus is 56.
• Some passengers have Rs 8 ticket and remaining having Rs 10 tickets.
• Total money received from the passengers is Rs 500

To Find:

• Number of passengers with each type of tickets.

Solution: Let the number of passengers with Rs 8 tickets be x therefore number of passengers with Rs 10 tickets be (56 – x).

A/q

$\small\implies{\sf }$ 8(x) + 10 (56 – x) = 500

$\small\implies{\sf }$ 8x + 560 – 10x = 500

$\small\implies{\sf }$ – 2x = 500 – 560

$\small\implies{\sf }$ – 2x = – 60

$\small\implies{\sf }$ 2x = 60

$\small\implies{\sf }$ x = 60/2

$\small\implies{\sf }$ x = 30

Hence, Passengers with Rs 8 tickets is x = 30 and passengers with Rs 10 tickets is (56 – x) = 56 – 30 = 26

Answer 2

Answer:

Step-by-step explanation: