a bus is initally moving at 18km/h and uniform acceleration at the rate of 5m/s² for 8sec. calculate (1) the final velocity and (2) the distance covered by it form the start.
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Initial Velocity is 18 km/h = 5m/s
Acceleration is 5m/s^2
Time is 8 seconds
(1) v = u + at
v is final velocity, u is initial velocity, a is acceleration , t is time
v = 5 + 40 = 45 km/h
(2) v^2 - u^2 = 2as
v is final velocity, u is initial velocity, a is acceleration, s is distance
2as = 45^2 - 5^2
2as = 2000
s = 200 m
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