Question

a bus is moving along a straight road with uniform acceleration.p and q are two marks on a road. the bus crosses the mark Q with a velocity 17/7 times the velocity of bus at the mark P . If the velocity of the bus at the midway of PQ is 26m/s, find the velocities of the bus at P and Q


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Answer 1

q=17/7×26=63m/s

p=26m/s

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Answer 2

Answer:

14m/s , 34m/s

from p to m

u=u

v=26m/s

s=s÷2

v2-u2=2as

26