Question

A bus is moving along a straight road with uniform acceleration.p and q are two marks on a road. the bus crosses the mark Q with a velocity 17/7 times the velocity of bus at the mark P . If the velocity of the bus at the midway of PQ is 26m/s, find the velocities of the bus at P and Q If the answer is correct I will mark you as brainliest!!

Answer 1

Answer:

q=17/7×26=63m/s

p=26m/s

Explanation:

Answer 2

Answer:

35.35kmph

Explanation:

v=u+at

40=30+at

at=10

v

2

=u

2

+2as

40

2

=30

2

+2as

2as=700

Now at midway s

1

=

2

s

v

2

=u

2

+2a

2

s

v

2

=30

2

+

2

700

=900+350

v

2

=1250

v=

1250

=35.35 kmph