Question

A bus is moving along a straight road with uniform acceleration.P and Q are two marks on the road .The bus crosses the mark Q with velocity 17/7 times the velocity of bus at the mark P . If the velocity of bus at the midway 26m/s,findrhe velocities of nisat P andQ

Answer 1

Answer:

v^2=u^2+2as

let u = x

v = (17/7)x

(17x/7)^2 = x^2 + 2as.... (1)

At midway distance = s/2

26^2 = x^2 + 2a(s/2)=x^2 +as

as = 26^2 - x^2

put this value of as in (1)

(17x/7)^2 = x^2 + 2(26^2 - x^2)

(17x/7)^2+ x^2 = 2×26×26

x^2 = 2×26×26×7×7/(17×17+49) = 196

x^2 = 196

x = 14 =u

v = (17/7)×14 = 34