Question

A bus is moving at 10 m/s. Driver increased its speed  to 25 m/s in 5 sec. find average velocity and from that find distance travelled by bus in that 5 seconds.​

Answer 1

Answer:

Distance travelled in Accelerating 5sec. = 87.5 m

Average velocity = 14.5 m/s

Explanation:

From the question :-

Bus moving from 10 m/s

Increased to 25 m/s in 5 sec.

To find : Average velocity and

Distance travelled by the bus in Accelerating 5 sec.

Solution :-

Initial velocity = u (10 m/s)

Final velocity = v (25 m/s)

Time taken = t ( 5 sec.)

Acceleration = a

Distance = s

Finding acceleration :-

a = v-u/t

a = 25-10/5

a = 15/5

a = 3 m/s²

Finding distance travelled by bus in Accelerating 5sec.

(By second Kinematical equation)

s = u*t + 1/2*a*t²

s = 10*5 + 1/2*3*5²

s = 50 + 75/2

s = 100+75/2

s = 175/2

s = 87.5 m

Finding average velocity :-

sum of velocities / no. of velocities

10 + 25 / 2

35/2

14.5 m/s