A bus is moving at a speed of 10 m/s is stopped by applying brakes which produce a uniform acceleration of 0.5 m /s^2 .How much distance will it covered by the bus before its stops ?
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Solution: Using equations of motion,
we get v = u + at
t = -u/a = -10/-0.5 = 20 s
s = ut + 1/2 at^2 = 10*20 - 1/2 (0.5*20^2) = 200 - 100 = 100 m
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it move by 300 m before it stop
ans 300m
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