Question

a bus is moving at a speed of 20 m/s, when it begins to slow at a constant rate of 5 m/s^2 in order to stop at a bus stop. if it comes to rest at the bus stop, how far away was the bus stop?

Answer 1

Answer:

Explanation:

a= 5 m/s^2

u= 20m/s

v= 0 (bus comes to rest)

s=?

Using third equation of motion, 2as= v^2-u^2

= 2*5*s= 0-400

= 10s=-400

= s = 40 m

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