Question

a bus is moving at a speed of 40 km/hr due north east and a cyclist is moving at a speed of 10 km/ he due north. what is the velocity of bus with respect to the cyclist?​

Answer 1

40km/hr, at an angle tan−1(35) east of south

50km/hr, at an angle tan−1(35) east of south

40km/hr, at an angle tan−1(34) east of south

50km/hr, at an angle tan−1(34) east of south

Answer :

d

Solution :

v→A=40jˆ,v→B=30iˆ

v→B/A=v→B−v→A=30iˆ−40jˆ

∣∣–→(B/A)∣∣=302+402−−−−−−−−√=50km/h

Answer 2

Answer:

nooooooooooooooooooooooooooooooooooooooo