Math, asked by ravichandratiwpaocwa, 1 year ago

A bus is moving at the speed of 40 2/5 km/h. how far will it travel in 6 2/3 hours?if the bus is still at a distance of 10 2/5km from the final destination; how far is the final destination from the starting point? ans. is 269 1/3,280km.

Answers

Answered by GouravSinghKV

speed= d/t
d= speed * t
= (40 2/5 km/h) * 6 2/3 h
= 202/5 * 20/3
= 4040/15
=269.33 km

arre aapko to ans pata h faltu mein itna sara likhwaya

ravichandratiwpaocwa: sir plz 2nd ka ans. bata dijiye .

GouravSinghKV: starting destination se final destination ke liye simply 269 1/3 mein 10 2/3 add karlo

GouravSinghKV: total distance = 269 1/3 +10 2/3 = 280 km

ravichandratiwpaocwa: thanx very much sir.bhut der se pareshan the

GouravSinghKV: wlcm

GouravSinghKV: i m in 10 th class

GouravSinghKV: sir matt bolo

ravichandratiwpaocwa: sir k liye koi age ya class ki eligibilty maine khin nhi padha hai jo helpful ho wahi sir hai or wahi mahan hai.

GouravSinghKV: nice thinking

GouravSinghKV: thanks

Answered by ishu46740

Answer:

speed of the bus = 40 2/5 = 202/5

time taken = 6 2/3 hours = 20/3 hours

distance covered by bus = 202/5 * 20/3 = 4040/15 km

distance from the final point = 10 2/3 = 32/3 km

total distance from starting to final point = 4040/15 + 32/3 = 4200/15 = 280 km

therefore distance from the final point = 32/3 - 280/1 = 808/3 = 269 1/3 km

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