A bus is moving at the speed of 40 2/5 km/hr. How much distance will it travel in 6 2/3 hrs.? If the bus is still at a distance of 10 2/3 km from the final destination. How far is the final destination from the starting point?
Answers
Answered by
0
Answer:
269.33 km
Step-by-step explanation:
speed= d/t
d= speed * t
= (40 2/5 km/h) * 6 2/3 h
= 202/5 * 20/3
= 4040/15
=269.33 km
Answered by
6
Answer:
distance traveled = 808/3 km
total distance = 280km
Step-by-step explanation:
distance traveled in (6+2/3) hrs = (40+2/5) × (6+2/3)
=> distance = (202/5)×(20/3) = 808/3
distance between starting point and final destination = distance covered + distance left
=> distance between initial and final destination = (808/3) + (10+2/3)
=> (808/3) + (32/3) = (808+32)/3
=> 840/3 = 280 km
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