Question

A bus is moving
on a road with 15ms and it
accelarates at 5ms. find the final velocity of
bus after 6 Second​

Answer 1

Answer:

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Explanation:

Given :-

The speed of the bus = 15m/s

The acceleration of bus = 10m/s²

Time taken by the bus = 5s

To Find :-

The final velocity of bus (v) = ?

The distance covered by the bus (s) = ?

Solution :-

To calculate the final velocity of bus and distance travelled by the bus , at first we have to use first equation of motion to calculate final velocity of the bus then calculate distance travelled by the bus by applying 2ns equation of motion.

Calculation for Final velocity :-

V = ? U = 15m/s. T = 5s. A = 10m/s² :-

⇢ First equation of motion :-

⇢ V = U + A × T

⇢ V = 15 + 10 × 5

⇢ V = 15 + 50

⇢ V = 65m/s

Therefore, final velocity of the bus (v) = 65m/s

Calculation for Distance covered by bus :-

S = ? U = 15m/s. T= 5s. A = 10m/s²

⇢ 2nd equation of motion :-

⇢ S = UT + 1/2 × A × T²

⇢ S = 15 × 5 + 1/2 × 10 × 5²

⇢ S = 75 + 5 × 25

⇢ S = 75 + 125

⇢ S = 200m

Therefore, distance covered by the bus (s) = 200m

Answer 2

Given: A bus is moving on a road with 15 m/s and it accelerates at 5m/s^2

To find: Final velocity of the bus after 6 seconds

Explanation: Let the initial velocity of the bus speed be denoted by u, final velocity be denoted by v and acceleration of the bus be denoted by a.

Then, u = 15 m/s

a= 5 m/s^2

Time duration= 6 seconds

Using kinematics formula:

v = u + at

= 15+5*6

= 15+30

= 45 m/s

Therefore, final velocity of the bus after 6 seconds is 45 m/s.