Question

a bus is moving on a road with 15ms and it accelerates at 5ms. Find the final velocity of a bus after 6 seconds​

Answer 1

Required Answer :

As per the provided information in the given question, we have been given that the bus is moving on a road with 15 m/s and it accelerates at 5 m/s². Now, we have been asked to calculate the final velocity of the bus after 6 seconds. Considering the provided information we have,

• Initial velocity, u = 15 m/s
• Acceleration, a = 5 m/s²
• Time taken, t = 6 seconds

In order to calculate the final velocity of a bus after 6 seconds, we'll have to apply the equations of kinematics. Here, we have u, a and v. So, by applying the first equation of motion, we can easily find the final velocity of a bus after 6 seconds.

First equation of motion is given by, $\bf v = u + at$ where $\rm v$ denotes final velocity, $\rm u$ denotes initial velocity, $\rm a$ denotes acceleration and $\rm t$ denotes time.

On substituting values,

$\implies \rm {v= u + at } \\ \\ \implies \rm { v = 15 + 5(6) \; ms^{-1} } \\ \\ \implies \rm { v = 15 + 30 \; ms^{-1} } \\ \\ \implies \boxed{ \bf { v = 45 \; ms^{-1}} }$

Therefore, final velocity of the bus after 6 seconds is 45 m/s.

$\rule{200}2$

Answer 2

Initial velocity  = u = 15 m/

        Acceleration = a = 5 m / s

       Time = t  = 6 sec

Now final Velocity = V = u + a × t         (  V = final velocity )

                                     = 15 +( 5 × 6 )meter per sec

                                       =  15 + 30 meter per second.

                                      ∴ V = 45 meter per sec

So the final velocity after 6 second will be 45 meter per second.