a bus is moving with 60km/h when breaks are applied it comes at rest after 2 sec find the distance travelled by it before coming rest.
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120 km, so easy ask something hard one
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Answer:
The distance traveled by bus before coming to rest is 16.63 m.
Explanation:
Initial velocity, u of the bus is 60 km/h = 16.67 m/s
When breaks are applied the bus comes to rest. So the final velocity of the bus will be 0. ie; v = 0.
The time taken for this is, t = 2 s
Acceleration of the bus can be found using the 1st equation of motion.
v = u + at
a = (v - u) / t
= (0 - 16.67) / 2
a = - 8.34 m/s²
Displacement can be found using the 3rd equation of motion.
v² = u² + 2aS
S = (v² - u²) / 2a
S = (0 - 16.67²) / (2 × -8.34)
S = 16.63 m
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