Physics, asked by kalitanitali9264, 1 year ago

A bus is moving with a constant acceleration a=3g/4 towards right. In the bus, a ball is tied with a rope of length l and is rotated in vertical circle as shown

I) at what value of the that tension in the rope will be minimum?

ii) at above mentioned position find the minimum possible speed Vmin during while path to complete the circular motion.

Iii) for above value of Vmin find maximum tension in the string during circular motion

Answers

Answered by brokendreams
0

ANSWER:

   The bus is moving at an acceleration of a=\frac{3}{4} g , a ball is rotated in the bus, if the starting point of the pendulum is B, then as the time goes on it passes point A with an opposite acceleration of a=\frac{3}{4} g and with opposing force of F=m \frac{3}{4} g. Therefore, due to low tension at the point B, due to attraction forces of the gravity “G”.  

i) The value of the tension will be minimum at B

ii) The minimum possible speed in terms of acceleration can be defined as

m \frac{v_{\min }^{2}}{r}=m a

m \frac{v_{\min }^{2}}{r}=m \frac{3}{4} a

v_{\min }=\sqrt{\frac{3 r a}{4}}

iii) The maximum tension due to minimum velocity and gravity will be observed at point A

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