A bus is moving with a constant velocity 10m/s on a straight road. a scooterist wishes to overtake the bus in 100s . if the bus is at distance of 1km from the scooterist ,then the velocity with which scooterist should chase the bus is?
Answers
Answered by
863
Given:
Time(t)= 100 s , distance (s)=1km= 1000m
Vb=10m/s (relative speed with respect to the bus)
Velocity (V)=distance /time = 1000/100= 10m/s
Vs= velocity of scooter, Vb=velocity of bus
V = Vs-Vb (both bus & scooter are moving in the same direction)
10= Vs-10
10+10 = Vs
20=Vs
Vs=20m/s
--------------------------------------------------------------------------------------------
The velocity with which scooterist should chase the bus is20m/s
----------------------------------------------------------------------------------------------
Hope this will help you.....
Time(t)= 100 s , distance (s)=1km= 1000m
Vb=10m/s (relative speed with respect to the bus)
Velocity (V)=distance /time = 1000/100= 10m/s
Vs= velocity of scooter, Vb=velocity of bus
V = Vs-Vb (both bus & scooter are moving in the same direction)
10= Vs-10
10+10 = Vs
20=Vs
Vs=20m/s
--------------------------------------------------------------------------------------------
The velocity with which scooterist should chase the bus is20m/s
----------------------------------------------------------------------------------------------
Hope this will help you.....
Answered by
362
Given :
Velocity of bus = Vbus=10m/s
time=100sec
let V be the relative speed of the scooter with respect to bus.
Let Vs be the velocity of scooter.
As both are moving in the same direction:
V=Vs- Vbus
Vs=V+Vbus
Velocity=Distance/time
=1000/100
=10m/s
Vs=10+10
=20m/s
∴The man on scooter should chase the bus at the speed of 20m/s
Velocity of bus = Vbus=10m/s
time=100sec
let V be the relative speed of the scooter with respect to bus.
Let Vs be the velocity of scooter.
As both are moving in the same direction:
V=Vs- Vbus
Vs=V+Vbus
Velocity=Distance/time
=1000/100
=10m/s
Vs=10+10
=20m/s
∴The man on scooter should chase the bus at the speed of 20m/s
Similar questions