A bus is moving with a speed of 36 km/h for the first hour and then with a speed of
50 km/h for the next hour. Find the total distance covered by the bus and also the
average speed.
Answers
Answer:
Total distance = 86 km
Average speed = 43 km/h
Explanation:
Total distance :-
Distance covered by the bus in the first hour :-
Speed = 36 km/h
Time = 1 hour
Distance = Speed * Time
= 36 * 1
= 36 km --D1
Distance covered by the bus in the second hour :-
Speed = 50 km/h
Time = 1 hour
Distance = Speed * Time
= 50 * 1
= 50 km --D2
Total distance covered by the bus in the two hours :-
D1 + D2
36 km + 50 km
86 km
Average speed :-
Speed in first hour = 36 km/h --S1
Speed in second hour = 50 km/h --S2
Total time = 1 hour + 1 hour
= 2 hour --T
Average speed = S1 + S2 / T
= 36 + 50 / 2
= 86 / 2
= 43 km/h
Answer:
Total distance = 86 km
Average speed = 43 km/h
Explanation:
Total distance :-
Distance covered by the bus in the first hour :-
Speed = 36 km/h
Time = 1 hour
Distance = Speed * Time
= 36 * 1
= 36 km --D1
Distance covered by the bus in the second hour :-
Speed = 50 km/h
Time = 1 hour
Distance = Speed * Time
= 50 * 1
= 50 km --D2
Total distance covered by the bus in the two hours :-
D1 + D2
36 km + 50 km
86 km
Average speed :-
Speed in first hour = 36 km/h --S1
Speed in second hour = 50 km/h --S2
Total time = 1 hour + 1 hour
= 2 hour --T
Average speed = S1 + S2 / T
= 36 + 50 / 2
= 86 / 2
= 43 km/h