Question

A bus is moving with a speed of 36km/h on applying breaks it stops in 8second find out the acceleration

Answer 1

• Initial velocity (u) = 36 km/hr.

• Final velocity (v) = 0 km/hr.

• Time (t) = 8 sec

__________ [ GIVEN ]

We have to find the acceleration (a) of the bus.

____________________________

We know that..

$\star \: { \bold{\boxed{v \: = \: u + \: at}}}$

(Newton's first equation of Motion)

Put the known values in above formula.

Before that, convert Initial velocity in m/s.

To convert km/hr into m/s. Multiple it with 5/18

=> u = 36 × 5/18

=> 10 m/s

Now.. Put them in above formula

=> 0 = 10 + a(8)

=> - 10 = 8a

=> 8a = - 10

=> a = - 1.25 m/s²

_____________________________

- 1.25 m/s² is the acceleration of the bus.

___________ [ ANSWER ]

_____________________________

Answer 2

$\huge\bf{Answer:-}$

According to the given question we

have to find the acceleration.

$= v=u+at$

$= u = 36 × 5/18$

$=10 m/s$

Using formula

$= 0 = 10 + a(8)$

$= - 10 = 8a$

$= 8a = - 10$

= a = - 1.25 m/s²

Therefore, - 1.25 m/s² is the acceleration of bus.