Question

a bus is moving with a speed of 72 kilometre per hour on applying brakes it comes to rest in 5 seconds find the acceleration and the distance travelled by the bus before coming to rest

Answer 1

Acceleration= (final velocity - Initial velocity)/Time

In this case u=72km/hr=72000/3600=20m/sec
v=0km/hr (rest)
T=5sec
Acceleration= (0-20)/5
-20/5= -4m/sec^2

Answer 2

U=initial speed=72km/h=20 m/sec.
v=final speed  =0 km/h
time=t= 5 sec.

v=u+at
v-u=at= v-u/t=a
-20/5= -4 m/sec^2 = deacceleration

now using the eqn:-

S=ut+1/2 a

S=20*5 +  (-4) * 5*5

S=100 - 50 =50 m.


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