Question

A bus is moving with a speed of 8 m\scan be stopped by applying breaks,after travelling a distance of 4 m the deceleration of bus is​

Answer 1

here we apply third equation of motion

Explanation:

v*2-u*2=2as

0-8*2=2a4

64=2*a*4

64/4=2a

16=2a

16/2=a

8=acceleration