Physics, asked by shrutisingh5950, 8 months ago

a bus is moving with a velocity of 40 ms-1 second a force of 1000 newton is applied and it comes to rest in 5 seconds calculate the retardation and mass of the bus and change in momentum brainly???
please answer asap ​

Answers

Answered by Yuseong
6

Explanation:

As per the provided information in the given question, we have :

  • Initial velocity (u) = 40 m/s
  • Force (F) = 1000 N
  • Final velocity (v) = 0 (as it comes to rest)
  • Time taken (t) = 5 seconds

We are asked to calculate,

  • Retardation
  • Mass of the bus (m)
  • Change in momentum

Calculating the retardation :

In order to calculate the retardation, firstly we need to find the acceleration. As we know that,

\longmapsto\bf { a = \dfrac{v-u}{t} } \\

  • v denotes final velocity
  • u denotes initial velocity
  • a denotes acceleration
  • t denotes time

\longmapsto\rm { a = \dfrac{0-40}{5} } \\

\longmapsto\rm { a = \dfrac{-40}{5} } \\

\longmapsto\bf { a = -8\; ms^{-2}} \\

As the acceleration of the bus is -8 m/s², so the retardation of the car will be 8 m/s².

\longmapsto\bf { Retardation = 8\; ms^{-2}} \\

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Calculating the mass of the bus:

As we know that,

\longmapsto\bf { F = ma } \\

  • F denotes force
  • m denotes mass
  • a denotes acceleration

\longmapsto\rm { 1000 = m \times (-8) } \\

\longmapsto\rm { \dfrac{1000}{-8} = m  } \\

\longmapsto\rm { -125 = m  } \\

As the mass can't be considered negative, so,

\longmapsto\bf { 125 \; kg = m  } \\

Therefore, mass of the bus is 125 kg.

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Calculating change in momentum :

\longmapsto\bf { \Delta p = mv - mu} \\

  • p denotes change in momentum
  • mv denotes final momentum
  • mu denotes initial momentum

\longmapsto\rm { \Delta p = 125(0) - 125(40) \; kg.ms^{-1}} \\

\longmapsto\bf { \Delta p =0 - 5000 \; kg.ms^{-1}} \\

Therefore, change is momentum is -5000 kg.m/s.

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