Question

a bus is moving with a velocity of 60 kilometre per hour is stopped by applying brakes suddenly in a time 5 seconds the Mass of the bus is 1000 kg . find the force applied to stop the bus​

Answer 1

Given that ,

• Initial velocity (u) = 60 km/hr or 16.6 m/s
• Final velocity (v) = 0
• Time (t) = 5 sec
• Mass of a car (m) = 1000 kg

We know that ,

$\sf \star \: \: \fbox{Force = Mass × Acceleration } \\ \\ \sf \star \: \: \fbox{Force = m × ( \frac{v - u}{t} ) }$

Thus ,

$\sf \mapsto Force = 1000 \times \frac{(0 - 16.6)}{5} \\ \\\sf \mapsto Force = 200 \times 16.6 \\ \\\sf \mapsto Force = 3320 \: \: n$

$\therefore \underline{\sf{The \: force \: applied \: by \: the \: bus \: is \: 3320 \: newton}}$

Answer 2

Answer:

Given:

• A bus is moving with a velocity of 60 kilometre per hour is stopped by applying brakes suddenly in a time 5 seconds the Mass of the bus is 1000 kg.

Find:

• Find the force applied to stop the bus.

Using force formula:

★ ${\sf{\underline{\boxed{\orange{\sf{Force = Mass \times Acceleration}}}}}}$

Note:

• 'F' as force.
• 1 km/hr ⇒ 0.278 m/s
• 1 km ⇒ 1000 m
• 1 hr ⇒ 3600 sec
• 1 km/hr ⇒ 1000/3600 ⇒ 5/18
• 5/18 km/hr ⇒ 0.277777778 m/s
• hence, 60 km/hr ⇒ 16.6 m/s

Calculations:

$\longrightarrow\bold{F = 1000 \times \: \dfrac{0 - 16.6}{5}}$

$\longrightarrow\bold{F = 1000 ÷ 5}$

$\longrightarrow\bold{F = 200 \times 16.6}$

$\longrightarrow{\sf{\underline{\boxed{\red{\sf{3320 \: N}}}}}}$

Therefore, 3320 N is the force applied to stop the bus.