Question

A Bus is moving with accelerated 4m/s2 from rest. Find the distance tavelled by the Bus in 5 second​

Answer 1

Given :

• Initial velocity, u = 0 m/s (starting from rest)

• Acceleration, a = 4 m/s²

• Time, t = 5 seconds

To find :

• Distance travelled by the bus, s

According to the question,

By using Newtons second equation of motion,

→ s = ut + ½ at²

Where,

• a = Acceleration
• s = Distance travelled
• t = Time
• u = Initial velocity

→ s = 0 × 5 + ½ × 4 × 5 × 5

→ s = 0 + 2 × 25

→ s = 0 + 50

→ s = 50

So,the distance travelled by the bus is 50 m.

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More formulas :-

Newton's first equation of motion :

• v = u + at

Newton's second equation of motion :

• s = ut + ½ at²

Newton's third equation of motion :

• v² = u² + 2as

Answer 2

u = 0 m/s

a = 4 m/s²

t = 5 s

We know,

s = ut + ½at²

$\therefore$ s = (0)t = ½at²

$\longrightarrow$ s = ½at²

$\longrightarrow$ s = ½(4 m/s²)(5 s)²

$\longrightarrow$ s = (2 m/s²)(25 s²)

$\longrightarrow$ s = 50 m (Answer)