A bus is moving with an initial velocity 10m/s.After 2 seconds,the velocity becomes 20m/s.find the acceleration and distance taken by the bus.
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Answer:
In the question,
Initial velocity = 10 m/s
Final velocity = 20 m/s
time taken = 2 s
Using the equations of motions:
= > v = u + at
= > 20 = 10 + 2a
= > 10 = 2a
= > 5 = a
Acceleration of the bus is 5 m/s^2
= > v^2 = u^2 + 2aS
= > 20^2 = 10^2 + 2(5)S
= > 400 = 100 + 10S
= > 400 - 100 = 10S
= > 300 = 10S
= > 30 = S
Henceforth, distance covered by the bus is 30 m.
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