A bus is moving with the initial
velocity of 'u' m/s. After applying the
breaks, its retardation is 0.5 m/s2 and it
stoped after 12s. Find the initial velocity
(u) and distance travel by the bus after
applying the breaks.
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Answer:
in first case final velocity becomes 0 as the body is coming in rest
so by applying v= u+ at
We get u = 6 m/s
and now putting values in S= ut+1/2 at2
We will get the Distance covered
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