Question

a bus is moving with the initial velocity of 'u' m/s .after applying the breaks ,it's retardetion is 0.5 m/s and it stopped after 12s . find the initial velocity (u) and distance travel by bus after applying the breaks

Answer 1

4 is wrong answer I don't know the right answer

Answer 2

v=0m/s (as it stops)
t=12s
a=-0.5m/s(retardation)

a=v-u/t
-0.5=0-u/12
-0.5*12=-u
u=6m/s

s=ut+1/2at^2
s=6*12+1/2*-0.5*12^2
s=72+1/2*-0.5*144
s=72-0.5*72
s=72-36
s=36m