A bus is moving with the velocity of 108 km/h. On the application of breaks it comes to rest in 4 seconds. Find the distance travelled by the bus before coming to rest.
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Force=mass*acceleration
f=m×
t
v−u
f=1000×
4
0−108×
18
5
=1000×(−7.5)
∴f=−7500N
opposing force is denoted by negative sign.
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