Physics, asked by Gohanuwu, 5 months ago

A bus is moving with the velocity of 108 km/h. On the application of breaks it comes to rest in 4 seconds. Find the distance travelled by the bus before coming to rest.

Answers

Answered by hemanthkumar76
5

Force=mass*acceleration

f=m×

t

v−u

f=1000×

4

0−108×

18

5

=1000×(−7.5)

∴f=−7500N

opposing force is denoted by negative sign.

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