Question

a bus is moving with the velocity of 60 km per hour by seeing a baby 11 m ahead the driver applied the brakes and the retardation produce is 13.88 metre per second square calculate the distance covered by the bus and the time taken to stop the bus​

Answer 1

Answer:

initial velocity (u)=0 m/s

final velocity (v)=60km/h

                         =60*1000/3600 (changing it in m/s²)

                         =16.66 m/s²

Retardation(-a)=13.88 m/s²

Distance(s)=?

or, v²-u²=2as

 or,16.66²-0=2*-13.88*s

or,277.55= -27.76s

or,277.55/-27.76=s

or, s= -9.998

Since distance can't be negative,s=9.998 m

  now

time(t)=?

s=u+v/2*t

9.998=0+16.66/2*t

9.998=8.33t

9.998/8.33=t

t=0.14 sec   ans..

Explanation: