Question

A bus is moving with velocity of 60 km/h when breaks are applied it comes to rest after
2 second. Find the distance travelled by it, before coming to rest.

Answer 1

Explanation:

velocity = 60km/h

t=2sec

change in h

2/3600 h

t=(1/1800)h

s={v+u/2}t

=30x1/1800

=1/60 km

=1000/60

=100/6m

Answer 2

Answer:

Distance travelled = 50/3 m

Explanation:

Initial velocity = u = 60km/hr = 60 * 5/18 m/s = 50/3 m/s

Final velocity = v = 0m/s

Time taken = 2s

We know that,

Acceleration = a = Change in velocity/Time

a = (v - u)/t

a = (0 - 50/3)/2 = -50/6

a = -25/3 m/s²

From Newton's Laws of Motion

v² = u² + 2aS

0 = 2500/9 + 2 × -25/3 × S

50S/3  = 2500/9

S = 50/3 m