A bus is running with a velocity of 72 kilometre per hour. on seeing a boy on the road 65m ahead, the driver jammed on the brakes and the bus stopped with uniform retardation 5m per S square. Calculate the distance travelled by the bus and discuss whether the accident took place or not ? give me answer immediately.....
Answers
Answered by
5
Answer:
what should we be do?
Explanation:
please sorry
Answered by
2
Answer:
distance travelled by the bus is 40 m and hence the accident is avoided as the boy is standing 65m away
Explanation:
firstly we will find the time taken by the bus to stop and then we can find the distance travelled by the bus afer the breaks are applied
so,
v = om/s
u = 72 × 5/ 18 ( converting it into m/s by multiplying it with 5/18)
= 20m/s
a = - 5m/s^2 ( -ve sign as accerlation is _ve of the retardation )
by applying identity v = u +at
0 = 20 - 5 t
t = 4s
now s = ut + 1/2 at^2
s = 20 × 4 + 1/2× ( -5 ) × 4×4
= 80 - 40
= 40m
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