Question

a bus is running with a velocity of 72 km per hour and a driver apply break and after appling the break the bus become in rest after 18 second find the retardation this bus

Answer 1

Answer:

72, 54, 36, 18, 0

Explanation:

We simply divide 72 by 18= 4 + 1 =5 = Order given in answer respectively.

First, the speed is 72 km/hr. After 3.6 secs it reduces to 54 km/hr. After next

3.6 secs, it reduces to 36km/hr. Then after next 3.6 secs, it reduces to 18km/hr and finally after last 3.6 secs it comes to rest (0 km/hr)