Question

A bus is traveling at 72km/hr.Brakes are applied and the bus comes to a stop after 10m.Find the retardation of the brakes

Answer 1

Given:-

• Initial Velocity (U) = 72km/hr
• Distance (S) = 10m
• Final Velocity (V) = 0

To Find:-

• Deceleration of the brakes.

Solution:-

72km/hr

→ 72×5/18

U → 20m/sec

As, V²-U² = 2as

$→\;{\sf{0²-20² = 2×a×10}}$

$→\;{\sf{-20² = 20a}}$

$→\;{\sf{400/20 = a}}$

$→\;{\bf{a = 20m/s²}}$

Retardation = 20m/s².

Hope It Helps You ✌️

Answer 2

Answer:

by using

v²-u²=2as

72km/hr to m/s=72*5/18=20m/s
0²-20²=2*-a*10
=-400=-20a
a=400/20
a=20m/s²