Question

a bus is traveling at 72km/hr breaks are applied and the bus comes to a stop after 10m find the retardation of the break​

Answer 1

Explanation:

Given, initial velocity, u= 72km/hr= 20m/s

final velocity, v=0 m/s

time taken to stop, t= 10 min= 600 s

Using first equation of motion,

v= u+ at

=>0=20+ a*600

=>a=-20/600 m/s^2=-0.033m/s^2(answer)

so retardation is 0.033m/s^2

Or(in km/hr)

t= 1/6 hr

therefore,

0=72+a*(1/6)

a= 72*6=432 km/hr^2 (answer)

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