Question

A bus is travelling at a speed of 60 km/hour. On seeing a boy 11 m ahead on the
road, the driver of the bus applies brakes and the bus stops at a distance of 10 m.
What is its retardation and how long does it take to come at rest?

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Answer 1

Answer:

a= 13.889 m/s^2

 t = 1.2 sec

Explanation:

the initial speed of bus(u)= 60 km/hr = 16.667 m/s

the final speed of bus(v) = 0 km/hr

distance travelled (s) = 10m

we have

$\frac{(v^{2} -u^{2} )}{2s} = a$

((16.667)^2 -0)/(2*10) = a

a= 13.889 m/s^2

we know acceleration (a) = change in velocity(Δv) / time(t)

                                    13.889 =  (16.667-0) / t

                                              t = 1.2 sec