A bus is travelling at a speed of 72km/h brakes are applied so as to produce an acceleration of 0.5 m/s square . Find how far the bus will go before it is brought to rest.
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Given :-
Initial speed of the train, u = 72 km/h = 25 m/s
Final speed of the train, v = 0
Acceleration = - 0.5 m/s²
To Find :-
Distance acquired
Formula to be used :-
Third equation of motion:
v² = u² + 2 as
Solution :-
Putting all the value, we get
⇒ v = u2 + 2 as
⇒ (0)2= (25)2 + 2 ( - 0.5) s
⇒ s = 625 m
Hence, The train will cover a distance of 625 m before coming to rest.
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