A bus is travelling at speed of 15m/s. Then it accelerates for 5s at a rate of 10m/s2. Find the final velocity and distance covered by the bus during this process.
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Initial velocity (u) = 15m/s
Time (t) = 5 seconds
Acceleration 10m/s²
Final velocity (v) = ?
Distance (s) = ?
v = u + at
v = 15 + 10(5)
v = 15 + 50
v = 65 m/s
2as = v² - u²
2(10)(s) = (65)² - (15)²
20s = 4225 - 225
20s = 4000
s = 4000/20
s = 200 m
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Time (t) = 5 seconds
Acceleration 10m/s²
Final velocity (v) = ?
Distance (s) = ?
v = u + at
v = 15 + 10(5)
v = 15 + 50
v = 65 m/s
2as = v² - u²
2(10)(s) = (65)² - (15)²
20s = 4225 - 225
20s = 4000
s = 4000/20
s = 200 m
Hope it helps you
Mark me as a brainlist please ❤️❤️
Bye ☺️
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