A bus is travelling with a velocity of 60km/hr. Pressing the brakes suddenly, it is retarded to 0.5m/s². how far will it travel before coming to rest?
Answers
Explanation:
refer to the attachment
Answer:
The bus will travel 277.78m before coming to rest.
Explanation:
Given:
Initial velocity (u) = 60km/hr = (60×5)/18 m/s = 16.667m/s = 50/3 m/s
Retardation (a) = -0.5m/s²
Final velocity (v) = 0m/s
To find:
Distance traveled (s) =?
Solution:
It is given that the bus is retarded to 0.5m/s² by the application of brakes.
We have to find the distance traveled before the bus comes to rest.
We use the third equation of motion which is given as follows:
v² = u² + 2as
where v is the final velocity, u is the initial velocity, a is the acceleration or deceleration, and s is the distance traveled.
Substituting the given values, we get
v² = u² + 2as
0² = (50/3)² + 2(-0.5)s
0 = (2500/9) - s
s = 2500/9 m
s = 277.78m
Therefore, the distance traveled before the bus comes to rest is 277.78m
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