Question

A bus leaves Ernakulam at 6 in the morning and reaches thiruvanathapuram at 12 noon running 40km/h on average. To reach one hour earlier by how much should the average speed be increased

Answer 1

Answer:

8km/h

Step-by-step explanation:

initially t=6h

s=40km/h

D=40×6=240km

D is same

then t should become 5h

S=240/5=48km/h

48-40=8

Answer 2

The average speed should be increased by 8km/hr to reach one hour earlier.

Step-by-step explanation:

Since we have given that

Average speed = 40 km/hr

Bus leaves in the morning at = 6

Bus reached = 12 noon

Number of hours = 6 hours

So, Distance covered is given by

$Speed\times Time\\\\=40\times 6\\\\=240\ km$

So, if a bus to reach one hour earlier.

so, Number of hours = 5 hours

So, Average speed becomes,

$\dfrac{Distance}{Time}\\\\=\dfrac{240}{5}\\\\=48\ km/hr$

So, Difference between the speed = 48-40=8 km/hr

Hence, the average speed should be increased by 8km/hr to reach one hour earlier.

# learn more:

A bus leaves Ernakulam at 6 in the morning and reaches thiruvanathapuram at 12 noon running 40km/h on average. To reach one hour earlier by how much should the average speed be increased

https://brainly.in/question/13311985