Question

. A bus leaves one stop, accelerates at 2 m s-2 for 3 seconds, then travels at constant velocity for 4 minutes, then decelerates at 5 m s-2 to the next stop. What is the distance between the two stops?

Answer 1

Answer:

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Answer 2

Answer:

in acc

S= ut + 1/2at^2

S= 0t + 1/2 (2×9}=9

at const

v=u +at= 0+6=6m/s

in 4 min or 240 sec dist= 6×240=1440m

in decel.

v2- u2 =2as

0-36= 2*(-5)*S

S= 3.6

total S = 1452.6m