A bus leaves place A at 8.30AM. It reaches place B at A distance of 80km at 10.30AM.It makes scheduled halt of 30minutes & then starts for place C which is 60km from B. If it reaches C at 1pm. Find the average speed if the bus.
Answers
Answer:
leaving time of place A =8:30 AM
arrival time of place B= 10:30 AM
total distance between place A and place B=80 km
rest time at place B=30 minutes [10:30-11:00]
leaving time of place B=11:00 AM
arrival time of place C=01:00 PM
total distance between place B and place C=60 km
AVERAGE SPEED= TOTAL DISTANCE
---------------------------------
TOTAL TIME
80 km + 60 km
=----------------------------
2 hours+2 hours
(8:30-10:30=2 hours and 11:00-01:00=2 hours)
140 km
=. ---------------
4 hours
=> AVERAGE SPEED=35km/h
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speed = distance/time
now from AToB =80km
taken time = 8:30 to 10:30
Explanation:
speed = distance/time
now from AToB =80km
taken time = 8:30 to 10:30 =3 hrs
now speed = distance/time
=80/3
= 25 so speed = 25 kmph