Question

a bus leaves place A at 8:30am. it reaches place 'B' located at distance of 80km at 10:30am. it makes a sheduled halt of 30 minutes and then starts for place 'C' which is 60km from B if it reaches 'C' at 1pm .find the average speed of the bus.​

Answer 1

Average Speed = Total distance/Total time

total distance = 80km+60km

=140km

total time = 2 hours+30min(0.5hours)+2h

=4.5hours

=140/4.5

=31.1

Answer: 31.1km/h

Answer 2

Answer:

The bus leaves at 8;30 and reaches place B at 10:30. Meaning it took 2 hrs to reach there.

From place B it stops for 30 minutes meaning it started at 11:00 am. It reached place C at 1 pm meaning it took 2hrs.

You find the average by adding both and dividing by the number of times =

60 km + 80km= 140km/2 = 70 km

Therefore the average speed of the bus is 70km/2hrs = 35km per hour.

Explanation:

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