Math, asked by jeansingh1996, 10 months ago

A bus left from Suva for Lautoka by Kings Road with 50 passengers. When it reached Rakiraki, 2/5 the passengers got off. Then it left for Ba, where another 1/5 of the passengers got off. How many passengers got off in Rakiraki? • How many passengers got off in Ba? • How many passengers were in the bus when it left for Lautoka from Ba?

Answers

Answered by elowen1108
12

Answer:

10 passergeres got of bae

20 passergeres got of at rakiraki

so 20 passergeres were left

step-by-step explanation:

1/5 of 50 is 10

2/5 of 50 is 20

20+10=30

50-30 is 20

pls mark brainliest

Answered by mddilshad11ab
83

\sf\large\underline{Given:}

A bus left from Suva for Lautoka by Kings Road with 50 passengers. When it reached Rakiraki, 2/5 the passengers got off. Then it left for Ba, where another 1/5 of the passengers got off

\sf\large\underline{To\: Find:}

1. How many passengers got off in Rakiraki?

2. How many passengers got off in Ba?

3. How many passengers were in the bus when it left for Lautoka from Ba?

\sf\large\underline{Solution:}

We have,

  • Total number of passengers=50
  • Passengers got off in Rakiraki=2/5
  • Passengers got off in Ba=1/5

Number of passengers who got off in Rakiraki

➞2/5×50

➞2×10

➞20 Passengers

Number of passengers who got off in Ba

➞1/5×50

➞1×10

➞10

Total number of passengers who got off from the bus

➞Rakiraki's passengers+Ba's passengers

➞20+10

➞30 passengers

Number of passengers when the bus left for lautoka from ba

➞Total passengers- Total number of passengers who got of f fro the bus

➞50-30

➞20 passengers

Hence,

Passengers got off in Rakiraki=20

Passengers got off in Ba=10

Rest passengers in the bus when it left for lautoka from Ba=20

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