A bus left Kolkata at 7:30 AM and without halting any where on its way reached Dicha at 12 noon. If the uniform speed of the bus is 45 km/hour, let us find the distance of Digha from Kolkata
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solve" Abus left kolkata at 12pm -7:30am
4km 30 hour
(4×60+30)hours=270
speed km/hour
60 45
270 ?
=60:270::45:?
:270×45 =12,375
60÷12375=206.25
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